Question

How do you find g(f(x)) given `f(x)=4x+3` and `g(x)=x-2`?

Answer 1

See the entire solution process below:

Explanation:

To find `g(f(x))` you must substitute `color(red)(f(x))` or `color(red)(4x + 3)` for each occurrence of `color(red)(x)` in `g(x)`.

`g(color(red)(x)) = color(red)(x) - 2` becomes:

`g(color(red)(f(x))) = color(red)((4x + 3)) - 2`

`g(color(red)(f(x))) = color(red)(4x) + color(red)(3) - 2`

`g(color(red)(f(x))) = 4x + 1`