Question

If a spring has a constant of `4 (kg)/s^2`, how much work will it take to extend the spring by `63 cm`?

Answer 1

I got `0.8J`

Explanation:

We will need to do work `W` to extend the spring that, as a result, will acquire an Elastic Potential Energy equal to `1/2kx^2`:
so, the energy we put to extend the spring (as work) will be converted into potential energy and so for our system:
`W=1/2kx^2`
or (using meters for the elongation):
`W=1/2*4*(0.63)^2=0.7939~~0.8J`