How do you solve the system of equations 2x-y=71 and 3y=x using substitution?

1 Answer
Feb 17, 2017

(142/5 , 71/5)

Explanation:

2x-y=71 and 3y=x

you just substitute one equation into the other
since x=3y you can just insert that into 2x-y=71

2(3y)-y=71
6y-6=71
5y=71
y=71/5

then we plug this y-value into either equation
2x-71/5=71
2x=284/5
x=284/10=142/5

(142/5 , 71/5)