How do you factor #7x^2-847#? Algebra Polynomials and Factoring Factoring Completely 1 Answer MeneerNask Feb 17, 2017 You first try to divide #847div7=121# Explanation: So we now have #=7*(x^2-121)# Notice that #121=11^2# and you get the special product for the difference of two squares: #a^2-b^2=(a+b)(a-b)#: #=7(x+11)(x-11)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1239 views around the world You can reuse this answer Creative Commons License