Question

Question #9cb33

Answer 1

Approx. `3.5*m^3`

Explanation:

We assume ideality, and calculate the volume occupied by an equivalent molar quantity of Ideal Gas.

Depending on your syllabus, they probably have `"STP"` `-=` `1*atm`, and `273.15*K`:

`V=(nRT)/P=((4300*g)/(28.05*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx273.15*K)/(1*atm)`

`=3.438xx10^3*L`.

I have always these types of question abstract where they ask the VOLUME occupied by a given quantity of gas at a given temperature. This assumes a scenario where the gas is introduced to an piston that can expand against `1` `"atm"`. The piston must be pretty big. Anyway, you can revise this answer depending on your given definition of `"STP"`.