Question

How do you expand `log_b x^7`?

Answer 1

`log_b x^7=(7logx)/logb`

Explanation:

Using the identities `log_b a^m=mlog_b a` and `log_b a=loga/logb`,

`log_b x^7`

= `7log_b x`

= `(7logx)/logb`