How do you expand #log_b x^7#? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer Shwetank Mauria Feb 18, 2017 #log_b x^7=(7logx)/logb# Explanation: Using the identities #log_b a^m=mlog_b a# and #log_b a=loga/logb#, #log_b x^7# = #7log_b x# = #(7logx)/logb# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1780 views around the world You can reuse this answer Creative Commons License