If the imaginary unit #i# rational or irrational ?

1 Answer
Feb 19, 2017

The set of rational numbers is a subset of the real numbers

# QQ subset RR #

The set of rational numbers are those that are real but not rational

# P = RR-QQ#, (or #P = RR // QQ#)
# P subset RR#

And the real numbers are a subset of the complex number:

# RR subset CC #

And so #i=sqrt(-1) in CC cancel(in) RR => i cancel(in) P#

And so #i# is neither rational nor irrational, as these are reserved for real numbers only.

#i# is complex!