Question

How do you find the derivative of `f(x)= (x^2-1)/x`?

Answer 1

I would rewrite and avoid the quotient rule.

Explanation:

`f(x) = x-1/x`

So `f'(x) = 1+1/x^2 = (x^2+1)/x^2`

If you like using the quotient rule

`f'(x) = ((2x)(x)-(x^2-1)(1))/x^2`

`= (2x^2-x^2+1)/x^2`

`= (x^2+1)/x^2`