How do you solve #3y + 16= 76#?

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Answer 1 · 2017-02-20T04:04:03

See the entire solution process below:

Step 1) Subtract #color(red)(16)# from each side of the equation to isolate the #y# term while keeping the equation balanced:

#3y + 16 - color(red)(16) = 76 - color(red)(16)#

#3y + 0 = 60#

#3y = 60#

Step 2) Divide each side of the equation by #color(red)(3)# to solve for #y# while keeping the equation balanced:

#(3y)/color(red)(3) = 60/color(red)(3)#

#(color(red)(cancel(color(black)(3)))y)/cancel(color(red)(3)) = 20#

#y = 20#