Square A has a side length (2x−7) and Square B has side length (−4x+18). How much bigger is the perimeter of Square B than Square A?

1 Answer
salamat
Feb 21, 2017

=−24x+100 for 72<x<92

Explanation:

Perimeter of Square A = 4(2x−7)=8x−28 unit.
note : since the unit of length cannot be -ve value, therefore x>72 for Square A.

Perimeter of Square B = 4(−4x+18)=−16x+72 unit
note : since the unit of length cannot be -ve value, therefore x<184or92 for Square B.

Consideration to both of notes, the values x shall be 72<x<92
The different perimeter between Square B and Square A = Perimeter of Square B - Perimeter of Square A.

=(−16x+72)−(8x−28)

=−16x+72−8x+28

=−24x+100 for 72<x<92

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