How do you find the x and y intercepts of # 2x-3y= -12#?

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Answer 1 · 2017-02-22T20:40:39

See the entire solution process below:

To find the x-intercept by substitution set #y = 0# and solve for #x#:

#2x - (3 xx 0) = -12#

#2x - 0 = -12#

#2x = -12#

#(2x)/color(red)(2) = -12/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = -6#

#x = -6# for #y = 0# therefore the x-intercept is #-6# or #(-6, 0)#

To find the y-intercept by substitution set #x = 0# and solve for #y#:

#(2 xx 0) - 3y = -12#

#0 - 3y = -12#

#-3y = -12#

#(-3y)/color(red)(-3) = (-12)/color(red)(-3)#

#(color(red)(cancel(color(black)(-3)))y)/cancel(color(red)(-3)) = 4#

#y = 4# for #x = 0# therefore the y-intercept is #4# or #(0, 4)#