Question

How do you multiply `(3x-2)^2`?

Answer 1

`9x^2-12x+4`

Explanation:

`(3x-2)^2` can be expanded to `(3x-2)(3x-2)`
From here you can use the FOIL method to expand.

The "first" would be `3x*3x=9x^2`
The "outside" would be `3x*-2=-6x`
The "inside," `-2*3x=-6x`
And the "last," `-2*-2=4`

Putting the terms together you get
`9x^2-6x-6x+4`

And combining like terms
`9x^2-12x+4`