Question

Question #9adca

Answer 1

`-pi/6.`

Explanation:

Recall the following Defn. of `arc sin` function :

`arc sinx=theta, |x|le1 iff sin theta=x, theta in [-pi/2,pi/2].`

Now, `sin (-pi/6)=-sin(pi/6)=-0.5, &, -pi/6 in [-pi/2,pi/2]`

`:. arc sin(-0.5)=-pi/6.`