Question

Question #28493

Answer 1

(a) `-1.bar81`
(b) `-2`
(c) `-0.bar8`

Explanation:

(a) Given `V=IR`
For `R=1,` `I=2/1=2A`
For `R=1.1,` `I=2/1.1=1.bar81A`
`:.` the average rate of change of `I` with respect to `R` in the interval of interest is`=(2-1.bar81)/(1-1.1)=-1.bar81`

(b) `I=V/R`
`=>I=2/R`
To find rate of change we differentiate function `I` with respect to Resistance `R`.
`(dI)/(dR)=2xx(-1)R^-2`
`=>(dI)/(dR)=-2R^-2`
ROC at `R=1Omega`
`(dI)/(dR)|_1=-2xx(1)^-2`
`=>(dI)/(dR)=-2`

(c) `R=V/I`
`=>R=2/I`
To find rate of change we differentiate function `R` with respect to Current `I`
`=>(dR)/(dI)=-2I^-2`
ROC at `I=1.5A`
`(dR)/(dI)|_1.5=-2xx(1.5)^-2`
`(dR)/(dI)=-0.bar8`