Question

How do you find the roots of `.0625x^2=.125x+15` by factoring?

Answer 1

`x=1+-sqrt241`

Explanation:

`0.0625x^2=0.125x+15`

A good idea would be to remove the decimal coefficients. The smallest multiplicand which gives whole number coefficients is `16`, so we'll multiply the equation by `16`.

`x^2=2x+240`

`x^2-2x-240=0`

we can't factorise this equation so we're going to have to use the quadratic formula:

`x=(2+-sqrt(2^2-4(-240)(1)))/2=1+-sqrt(241)`