How do you solve #0\leq 4 x - 3 \leq 1 1#?

1 Answer
Jim G.
Feb 26, 2017

#3/4<=x<=7/2#

Explanation:

We want to #color(blue)"isolate"# x in the middle interval and have numeric values at the 2 other intervals.

add 3 to ALL parts.

#0+3<=4xcancel(-3)cancel(+3)<=11+3#

#rArr3<=4x<=14#

divide ALL parts by 4

#3/4<=(cancel(4) x)/cancel(4)<=14/4#

#rArr3/4<=x<=7/2" is the solution"#

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