What is the derivative of #ln3x#?
1 Answer
Feb 26, 2017
# dy/dx=1/x #
Explanation:
We will need the standard result:
#d/dx lnx=1/x#
By the rule of logs:
# y=ln3x #
# \ \ \=ln3+lnx #
# :. dy/dx=0+1/x = 1/x #
Or we can implicitly apply the chain rule:
# dy/dx = 1/(3x) * 3 = 1/x #