How do you find the derivative of #z=x(y^2)-e^(xy)#?
1 Answer
Feb 27, 2017
# (partial z) / (partial x) = y^2-ye^(xy) #
# (partial z) / (partial y) = 2xy-xe^(xy) #
Explanation:
We have:
#z=xy^2-e^(xy)#
Which is a function of two variables, so the derivatives are;
# (partial z) / (partial x) = y^2-ye^(xy) #
# (partial z) / (partial y) = 2xy-xe^(xy) #
Remember when partially differentiating: differentiate with respect to the variable in question, treating the other variables as constant.
