How do you solve #sqrt(x^2+9x+15)=x+5# and check your solution?
1 Answer
Feb 27, 2017
Explanation:
Square both sides:
#(sqrt(x^2 + 9x + 15))^2 = (x + 5)^2#
#x^2 + 9x + 15 = x^2 + 10x + 25#
#x^2 - x^2 + 9x - 10x + 15 - 25 = 0#
#-x - 10 = 0#
#x = -10#
Check:
#sqrt((-10)^2 + 9(-10) + 15) =^? -10 + 5#
#sqrt(25) != -5#
There is no solution to this equation.
Hopefully this helps!
