What is the moment of inertia of a pendulum with a mass of #6 kg# that is #7 m# from the pivot?

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Answer 1 · 2017-02-27T12:42:06

The moment of inertia is #=294kgm^2#

The moment of inertia is

#I=mr^2#

#m=6kg#

#r=7m#

#I=6*7^2=294kgm^2#

Answer 2 · 2017-02-27T12:42:49

#294 \ kg \ m^2#

For a point mass, which is a simplifying assumption:

#I = m r^2 = 6 * 7^2 = 294 \ kg \ m^2#