Question #eb29e

1 Answer
Andrew B.
Feb 27, 2017

1.87*10^231.87⋅1023 formula units of Ba(NO_3)_2Ba(NO3)2

Explanation:

First compute the molar mass of Ba(NO_3)_2Ba(NO3)2:

MM = 137.3g+(2*14.007g)+(6*15.999g)=261.3(gBa(NO_3)_2)/(mol)=137.3g+(2⋅14.007g)+(6⋅15.999g)=261.3gBa(NO3)2mol

Next use dimensional analysis to calculate the answer. Be sure to set up the units correctly and use appropriate conversions. Usually if you set up the units correctly, you'll get the correct answer.

(81.3cancel(gBa(NO_3)_2))((1cancel(molBa(NO_3)_2))/(261.3cancel(gBa(NO_3)_2)))((6.02*10^23FU)/(1cancel(molBa(NO_3)_2)))=1.87*10^23FU

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