How do you simplify #sqrt(27/a^2)#?

1 Answer
Feb 27, 2017

#=(3sqrt(3))/a#

Explanation:

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You are looking for squared values. They can be 'taken outside' the root.

You can write: #sqrt(27/a^2)" as "sqrt(27)/sqrt(a^2)#

If you are ever unsure of something try it out using easy numbers
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Write as:#" "sqrt(27)/sqrt(a^2) = sqrt(27)/a#

Known that #3xx9=27 = 3xx3^2#

Write as:#" "sqrt(3xx3^2)/a=(3sqrt(3))/a#