Question

How do you graph `3x+5y=-15` using intercepts?

Answer 1

Our intercepts are (-5,0) and (0,-3)

Explanation:

Solve for y:

`5y=-15-3x`

`y=-3-(3/5)x`

Plug in 0 for x:

`y=-3-(3/5)(0)=-3`

Plug in 0 for y:

`0=-3-(3/5)x`

Solve for x:

`3=-(3/5)x`

`-5=x`

So our intercepts are (-5,0) and (0,-3)

Now we can graph these points and connect them with a line.

graph{-3-(3/5)x [-10, 10, -5, 5]}