Question

How do you simplify `(2xyz)/(x^2z^2)div (6y^3)/(3xz)`?

Answer 1

`\frac{1}{y^2}`

Explanation:

When we divide one fraction with another one, we can rewrite it as multiplication of first fraction by the second one, it means:
`a/b -: c/d = a/b \times d/c = (ad)/(bc)`

so let's do the trick and see what'll happen
`\frac{2xyz}{x^2z^2} -: \frac{6y^3}{3xz} = \frac{2xyz}{x^2z^2} \times \frac{3xz}{6y^3}`

and we simply multiply the numerator by the numerator and the denominator by the denominator.
`\frac{2xyz}{x^2z^2} \times \frac{3xz}{6y^3} = \frac{6x^2yz^2}{6x^2y^3z^2}`
and by simplifying this fraction we get:

`\frac{6x^2yz^2}{6x^2y^3z^2} = \frac{1}{y^2}`