How do you find the first and second derivative of #y=e^x+e^-x#?
1 Answer
Mar 2, 2017
# dy/dx \ = e^x - e^(-x) #
# (d^2y)/(dx^2) = e^x + e^(-x) #
Explanation:
Using the standard result:
# d/dx e^(ax)=ae^(ax) #
Then if :
# y = e^x+e^(-x) #
We have:
# dy/dx \ = e^x - e^(-x) #
And then:
# (d^2y)/(dx^2) = e^x + e^(-x) #