How do you simplify # (sqrt3 - 2)^2#?
1 Answer
Mar 3, 2017
#(sqrt3-2)^2=(sqrt3-2)(sqrt3-2)#
FOILing this out:
#=(sqrt3)(sqrt3)-2sqrt3-2sqrt3-2(-2)#
#=3-4sqrt3+4#
#=7-4sqrt3#
