How do you solve #7x ^ { 2} - 10x = - 3#?

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Answer 1 · 2017-03-03T17:20:40

#x=1#

#7x^2-10x=-3#

#7x^2-10x+3=0#

#(7x-3)(x-1)=0#

#7x-3=0# or #x-1=0#

#7x=3# or #x=1#

#x=3/7# or #x=1#

substitute x=3/7

#7(3/7)^2-10(3/7)=-3#

#7(9/7)-30/7=-3#

#63/7-30/7=-3#

#33/7=-3#

#4 4/7=-3#

#x=3/7#= Extraneous solution

substitute #x=1#

#7(1)^2-10(1)=-3#

#7-10=-3#

#-3=-3#

#:.x=1#