Do the following equations define functions: (i) #y = x^2-5x# (ii) #x = y^2-5y# ?
1 Answer
Mar 4, 2017
See explanation...
Explanation:
First equation:
For the first equation, putting
#y = x^2-5x = (-6)^2-5(-6) = 36+30 = 66#
Note that the value of
graph{(y - x^2+5x)(x+6+0.0001y) = 0 [-11, 11, -11, 102]}
Second equation:
For the second equation, putting
#-6 = x = y^2-5y#
Adding
#0 = y^2-5y+6 = (y-2)(y-3)#
So
Note that
graph{(x - y^2+5y)(x+6+0.0001y) = 0 [-12, 2, -2.5, 6]}