How do you simplify #(15n^{2}-2n-24)\div (3n-4)#?

Question

777 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-04T15:14:06

See the entire simplification process below:

First, rewrite the expression as:

#(15n^2 - 2n - 24)/(3n - 4)#

Next, factor the numerator as:

#((3n - 4)(5n + 6))/(3n - 4)#

Now, cancel the common terms in the numerator and denominator:

#(color(red)(cancel(color(black)((3n - 4))))(5n + 6))/color(red)(cancel(color(black)((3n - 4)))#

#5n + 6#

However,

#(3n - 4)# cannot equal #0#

Or

#n# cannot equal #4/3#