How do you integrate #int dx#?

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Answer 1 · 2017-03-05T12:15:47

#x + C#

#intdx = int1dx = intx^0dx#

Using the standard power rule of integration,

#intx^0dx = x^(0+1)/(0+1) + C= x + C#

Answer 2 · 2017-03-05T12:16:17

#x+C#

#int dx = int x^0 dx#

Applying the power rule:

#int dx= x^(0+1)/(0+1) +C#

#=x+C#