Question

A charge of `24 C` passes through a circuit every `6 s`. If the circuit can generate `12 W` of power, what is the circuit's resistance?

Answer 1

`0.75Omega`

Explanation:

Calculate current, `I`, by

`I = Q/t = (24C)/(6s) = 4A`

Electrical power is given by

`P = IV = I^2R`

so

`R = P/I^2 = (12W)/(4A)^2 = 0.75Omega`

Answer 2

`0.75Omega`

Explanation:

Calculate current, `I`, by

`I = Q/t = (24C)/(6s) = 4A`

Electrical power is given by

`P = IV = I^2R`

so

`R = P/I^2 = (12W)/(4A)^2 = 0.75Omega`