How do you solve 5x ^ { 2} + 3x - 55= 5?

1 Answer
Mar 7, 2017

(-3+sqrt1209)/10 or (-3-sqrt1209)/10

Explanation:

5x^2 + 3x - 55 = 5

=5x^2 + 3x - 60 = 0

standard equation of quadratic equation,
ax^2 + bx + c = 0

Here,
a = 5, b = 3 and c = 60

by formula,
x = [-b +- sqrt(b^2 - 4ac)]/(2a)

So, x = [-3 +- sqrt(9 + 1200)]/(10)

therefore x = (-3+sqrt1209)/10 or (-3-sqrt1209)/10