How do you divide #(-15y^7z^4+21y^7z^6-97Y3z)-:(3y^5z^2)#?

1 Answer
Tony B
Mar 7, 2017

Assumption that you intended the question to be:
#(-15y^7z^4+21y^7z^6-97y^3z)-:(3y^5z^2)#

Solution:#-> -5y^2z^2+7y^2z^4-32 1/3y^(-2)z^(-1)#

Explanation:

#" "-15y^7z^4+21y^7z^6-97y^3z#
#color(magenta)(-5y^2z^2)(3y^5z^2)->ul(-15y^7z^4color(white)(00000) larr" subtract")#
#" "color(white)(000)0+21y^7z^6-97y^3z#
#color(magenta)(+7y^2z^4)(3y^5z^2)->" "color(white)(.)ul(+21y^7z^6color(white)(0)larr" subtract")#
#" "0-97y^3z#
#color(magenta)(-32 1/3y^(-2)z^(-1))(3y^5z^2)->" "ul(color(white)(0)-97y^3z larr" subtract")#
#" "0#

#color(magenta)(-5y^2z^2+7y^2z^4-32 1/3y^(-2)z^(-1)#

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