How do you express #4/3sqrt(162xy^6z^8# in simplest radical form?

1 Answer
MeneerNask
Mar 8, 2017

Factorize and try to find squares:

Explanation:

#162=2xx81=2xx9^2#
#y^6=(y^3)^2#
#z^9=(z^4)^2#

So, except for the #2# and the #x#, we can bring everything out from under the root:

#=4/3xx9xxy^3xxz^4xxsqrt(2x)#

#=12y^3z^4sqrt(2x)#

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