How do you solve #42=-3(6+v)#?

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Answer 1 · 2017-03-09T18:51:20

See the entire solution process below:

First, expand the terms within parenthesis on the right side of the equation by multiplying each term within the parenthesis by #color(red)(-3)#:

#42 = color(red)(-3)(6 + v)#

#42 = (color(red)(-3)xx6) + (color(red)(-3)xxv)#

#42 = -18 - 3v#

Next, add #color(red)(18)# to each side of the the equation to isolate the #v# term while keeping the equation balanced:

#color(red)(18) + 42 = color(red)(18) - 18 - 3v#

#60 = 0 - 3v#

#60 = -3v#

Now, divide each side of the equation by #color(red)(-3)# to solve for #v# while keeping the equation balanced:

#60/color(red)(-3) = (-3v)/color(red)(-3)#

#-20 = (color(red)(cancel(color(black)(-3)))v)/cancel(color(red)(-3))#

#-20 = v#

#v = -20#