Question

How do you solve `-x ^ { 2} + 2x + 3= x ^ { 2} - 2x + 3`?

Answer 1

The answers are `0` or `2`.

Explanation:

`-x^2 + 2x+3= x^2 - 2x+3`

`=> -x^2+2x+3-x^2+2x-3=0`

`=> -2x^2+4x=0`

`=> 2x^2-4x=0`

`=> x^2-2x=0`

`=> x(x-2)=0`

Hence, `x` is either `2` or `0`.