How do you solve #f^ { 2} + 26f + 25= 0#?

1 Answer
Alan N.
Mar 11, 2017

#f= -25 or -1#

Explanation:

#f^2+26f+25=0#

#(f+25)(f+1)=0#

#:. f+25 =0# or #f+1=0 -> f= -25 or -1#

NB: Although this is a simple example of solving a quadratic equation by factorisation, it is worth noting that using #f# to denote the variable could be a distraction as this is usually used to represent a function. Not in this case!

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