Question

What is the logarithmic form of the equation `e^(4x) = 2981`?

Answer 1

`x=1/4ln2981`

Explanation:

According to definition of logarithm if `a^b=x`, then `log_a x=b`, where `a` is called as base.

Further, when base is `10`, we just write `log` i.e. `log10` is nothing but `log_10 x`.

Many times we also use base as `e`, the Euler's number and we write `ln` in place of `log`.

As such `e^(4x)=2981` means

`log_e 2981=4x`

or `ln2981=4x`

and hence `x=1/4ln2981`