Question

What transition energy corresponds to an absorption line at 460 nm?

Answer 1

I got `4.3×10^(-19)J`

Explanation:

We can use Einstein's relationship for the energy:
`E=hf`
Where `f` is frequency and `h` is Planck's constant.
In numbers:
`E=6.63×10^(-34)*(3×10^8)/(460×10^(-9))=4.3×10^(-19)J`

Where:
`f=("speed of light")/("wavelength")`