How do you solve #t(2t+3)+20=2t(t-3)#?

1 Answer
Mar 12, 2017

t = -2.2222..., or t = #-20/9#

Explanation:

In this equation, we would first distribute the t through the (2t + 3), and distribute the 2t through the (t - 3). After doing so, you get, #2t^2 + 3t + 20 = 2t^2 - 6t#. Next, we would combine like terms getting,
#9t + 20 = 0#, where the two #2t^2#'s cancel each other out. Next, move the 20 to the other side, #9t = -20#. Finally, divide both sides by 9 to separate the t. Your final answer should be either, t = -2.2222..., or
t = #-20/9#.