How do you evaluate #log424#?
1 Answer
Mar 12, 2017
Explanation:
Suppose we know:
#log 2 ~~ 0.30103#
#ln 10 ~~ 2.3026#
#ln(1+x) = x-x^2/2+x^3/3-x^4/4+...#
Then:
#log 424 = log(2*2*10*10*1.06)#
#color(white)(log 424) = log 2 + log 2 + log 10 + log 10 + log 1.06#
#color(white)(log 424) ~~ 0.30103 + 0.30103 + 1 + 1 + (ln (1 + 0.06))/ln 10#
#color(white)(log 424) ~~ 2.60206 + (ln (1 + 0.06))/2.3026#
#color(white)(log 424) ~~ 2.60206 + (0.06-(0.06)^2/2+(0.06)^3/3)/2.3026#
#color(white)(log 424) = 2.60206 + (0.06-0.0018+0.000072)/2.3026#
#color(white)(log 424) = 2.60206 + 0.058272/2.3026#
#color(white)(log 424) ~~ 2.60206 + 0.025307#
#color(white)(log 424) ~~ 2.62737#