How do you solve #7\geq \frac { - 5h + 9} { 2} > - 3#?

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Answer 1 · 2017-03-13T03:22:21

#-1<=h<3# or

Interval notation: #[-1,3)#

#7>=(-5h+9)/2>##-3#

#7*2>=(cancel(2)(-5h+9))/cancel(2)>##-3*2#

#14>=-5h+9>##-6#

#14-9>=##-5hcancel(+9)cancel(-9)>##-6-9#

#5>=##-5h>##-15#

#(cancel(5)-1)/(cancel(-5)1)>=##(cancel(-5)h)/(cancel(-5)1)>##(cancel(-15)3)/(cancel(-5)1)#

remember to switch symbol direction after multiplying or dividing all sides by a negative number

#-1<=h<3#

Interval notation: #[-1,3)#
** "#[# #]#" for #>=#or #<=#, "#(##)#" for #># or #<#