Question

Question #de065

Answer 1

See the explanation

Explanation:

This is a variant on the standardised equation of a circle.

Basically, the equation construct is using a triangle where the 1 is the length of the hypotenuse and one of the corners (vertex) is at the origin of the graph (where the axis cross). So by using Pythagoras you have `x^2+y^2=r^2` where `r` (the hypotenuse) also represents the radius of a circle, the center of which coincides with the origin.

However, changing `y^2` to `(y-1)^2` bit moves the whole plot upwards by 1