# + 3x -( + 3x) = 0# so if the two equations are subtracted, the #x# term disappears.
#" "3x - 3y = -9#
#-3x - (-5y) = -( - 29)" "# This gives:
#0x + 2y = + 20" "# next solve for y by dividing both sides by 2
# (2y)/2 = 20/2" "# This gives :
# y = 10#
Next substitute #y =10 #into either of the equation and solve for #x#.
# 3x + (-3 )xx 10 = -9 # This gives
# 3x -30 = -9 " "# Add 30 to both sides giving
# 3x - 30 +30 = -9 +30" "# which gives
# 3x = + 21" "# Finally divide both sides by 3
# (3x)/3 = 21/3# The answer is
#x = 7 #
To make sure the answer is correct, substitute the values for# x and y # into the other equation to check the answer:
#3x -5y =-29#
# 3 xx 7 - 5 xx 10 = - 29" " # this gives
# + 21 -50 = -29" "# adding the integers gives
# -29 = -29" "# The answer checks.