Question

How do you graph using x and y intercept of `3x-4y+2=0`?

Answer 1

Please see below.

Explanation:

We can find `x`-intercept by putting `y=0` in the given equation `3x-4y+2=0` and `y`-intercept by putting `y=0` in the equation.

Hence `x`-intercept is given by `3x-4xx0+2=0` i.e. `x=-2/3` at `(-2/3,0)`

and `y`-intercept is given by `3xx0-4y+2=0` i.e. `y=1/2` at `(0,1/2)`

The graph will be obtained by joining `(-2/3,0)` and `(0,1/2)` and appears as given below.

graph{3x-4y+2=0 [-3.177, 1.823, -1.28, 1.22]}