How do you evaluate #58.3 times .13#?

2 Answers
Mar 17, 2017

#rArr7.579#

Explanation:

# 58.3 xx .13#

# rArr58.3 xx 0.13#

#rArr7.579#

Mar 20, 2017

#7.579#

Explanation:

#color(red)(" A different type of approach")#

If the decimal places are giving you a problem this is another way of approaching it.

#58.3# is the same as #583xx1/10#

#0.13# is the same as #13xx1/100#

So #58.3xx0.13# is the same as:

#583xx13xx1/10xx1/100#

#583xx13xx1/1000#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Dealing with "583xx13" part")#

13 can be split into #10+3#

#10xx583->5830#
#color(white)(1)3xx583->ul( 1749) larr" add"#
#" "7579#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Dealing with "xx1/1000" part")#

#7579xx1/1000 = 7.579#