How do you solve #3/(2x-1) - 4/(3x-1) = 1#?

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Answer 1 · 2017-03-17T13:29:13

#"answer is x=1"#

#3/(2x-1)-4/(3x-1)=1#

#(3(3x-1)-4(2x-1))/((2x-1)(3x-1))=1#

#3(3x-1)-4(2x-1)=(2x-1)(3x-1)#

#cancel(9x)-3-cancel(8x)+4=6x^2-2x-3x+1#

#x+1=6x^2-5x+1#

#6x^2-5xcancel(+1)-x cancel(-1)=0#

#6x^2-6x=0#

#cancel(6)x^2=cancel(6)x#

#cancel(x^2)=cancel(x)#

#x=1#