Question #26ac4 Trigonometry Trigonometric Identities and Equations Double Angle Identities 1 Answer Monzur R. Mar 17, 2017 See below Explanation: #cos2x=cos(x+x)=cosxcosx-sinxsinx=cos^2x-sin^2x# #therefore cos2x=cos^2x-sin^2x# ΟΕΔ/#QED"# Answer link Related questions What are Double Angle Identities? How do you use a double angle identity to find the exact value of each expression? How do you use a double-angle identity to find the exact value of sin 120°? How do you use double angle identities to solve equations? How do you find all solutions for #sin 2x = cos x# for the interval #[0,2pi]#? How do you find all solutions for #4sinthetacostheta=sqrt(3)# for the interval #[0,2pi]#? How do you simplify #cosx(2sinx + cosx)-sin^2x#? If #tan x = 0.3#, then how do you find tan 2x? If #sin x= 5/3#, what is the sin 2x equal to? How do you prove #cos2A = 2cos^2 A - 1#? See all questions in Double Angle Identities Impact of this question 1384 views around the world You can reuse this answer Creative Commons License