Question

Find f'(x) of this ?

Answer 1

`f'(x)=cosxcotx-cscx-cotxcscx+12/x^5`

Explanation:

`f(x)=sinxcotx+cscx-3/x^4`

Hence `f'(x)=d/(dx)(sinxcotx)+d/(dx)cscx-d/(dx)(3/x^4)`

= `(cosxcotx+sinx xx(-csc^2x))-cotxcscx-3xx(-4)xx1/x^5`

= `cosxcotx-cscx-cotxcscx+12/x^5`