How do you factor 81p ^ { 2} + 108p + 3681p2+108p+36?

1 Answer
Mar 18, 2017

(9p+6)^2(9p+6)2

Explanation:

Since

81p^2=(9p)^281p2=(9p)2

and

36=6^236=62

and

108p=2*9p*6108p=29p6,

then the given polynomial is the expanded square of the bynomial 9p+69p+6:

(9p+6)^2(9p+6)2